Advertisements
Advertisements
Question
The perimeter of the right angled triangle is 60cm. Its hypotenuse is 25cm. Find the area of the triangle.
Advertisements
Solution
Perimeter = a+b+h where a and bare sides and his hypotenuse. Here h= 25.
Given that a+b+ 25=60, hence a+b=35
⇒ a=35 - b ... (i)
Also, a2 + b2 = h2 = 625 ... (ii)
Putting (i) in (ii), we get,
(35 - b)2 + b2 = 625,
1225 + b2 -70 b + b2 = 625
2b2 - 7O b + 600 = 0 ,
Dividing by 2, we get: b2 - 35b + 300 = 0
⇒ b2 - 20b - 15b + 300 = 0
⇒ b(b-20)-15(b-20)=0
⇒ (b-20)(b-15)=0
⇒ b= 20 or 15
Hence if b = 20, a = 35 - 20 = 15 and area = `(20 xx 15)/2 = 150` cm2
APPEARS IN
RELATED QUESTIONS
Solve the following quadratic equations by factorization:
`a/(x-a)+b/(x-b)=(2c)/(x-c)`
Solve the following quadratic equations by factorization:
`x^2+(a+1/a)x+1=0`
Find the consecutive even integers whose squares have the sum 340.
Let us find two natural numbers which differ by 3 and whose squares have the sum 117.
Solve the following quadratic equations by factorization:
\[3\left( \frac{7x + 1}{5x - 3} \right) - 4\left( \frac{5x - 3}{7x + 1} \right) = 11; x \neq \frac{3}{5}, - \frac{1}{7}\]
Solve the following quadratic equation by factorisation:
x2 - 3x - 10 = 0
Solve the following equation by factorization
2x2 – 8x – 24 = 0 when x∈I
Solve the following equation by factorization
5x2 – 8x – 4 = 0 when x∈Q
Solve the following equation by factorization
`3x - (8)/x `= 2
Solve the following equation by factorisation :
`(6)/x - (2)/(x - 1) = (1)/(x - 2)`
