Advertisements
Advertisements
प्रश्न
The perimeter of the right angled triangle is 60cm. Its hypotenuse is 25cm. Find the area of the triangle.
Advertisements
उत्तर
Perimeter = a+b+h where a and bare sides and his hypotenuse. Here h= 25.
Given that a+b+ 25=60, hence a+b=35
⇒ a=35 - b ... (i)
Also, a2 + b2 = h2 = 625 ... (ii)
Putting (i) in (ii), we get,
(35 - b)2 + b2 = 625,
1225 + b2 -70 b + b2 = 625
2b2 - 7O b + 600 = 0 ,
Dividing by 2, we get: b2 - 35b + 300 = 0
⇒ b2 - 20b - 15b + 300 = 0
⇒ b(b-20)-15(b-20)=0
⇒ (b-20)(b-15)=0
⇒ b= 20 or 15
Hence if b = 20, a = 35 - 20 = 15 and area = `(20 xx 15)/2 = 150` cm2
APPEARS IN
संबंधित प्रश्न
Solve for x :
`1/(2x - 3) + 1/(x - 5) = 1 1/9 , X != 3/2, 5`
Find k if x = 3 is a root of equation kx2 – 10x + 3 = 0.
If \[x = - \frac{1}{2}\],is a solution of the quadratic equation \[3 x^2 + 2kx - 3 = 0\] ,find the value of k.
Solve the following equation: `("x" + 3)/("x" - 2) - (1 - "x")/"x" = 17/4`
Solve the following equation: abx2 +(b2-ac) x - bc = 0
The sum of the square of 2 consecutive odd positive integers is 290.Find them.
Car A travels x km for every litre of petrol, while car B travels (x + 5) km for every litre of petrol.
If car A use 4 litre of petrol more than car B in covering the 400 km, write down and equation in x and solve it to determine the number of litre of petrol used by car B for the journey.
Solve the following equation by factorization
x (2x + 1) = 6
Find the roots of the following quadratic equation by the factorisation method:
`2x^2 + 5/3x - 2 = 0`
If the area of a square is 400 m2, then find the side of the square by the method of factorization.
