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The Percentage Composition of Sodium Phosphate, as Determined by Analysis Is: 42.1% Na, 18.9% P, 39% of O. Find the Empirical Formula of the Compound.

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Question

The percentage composition of sodium phosphate, as determined by analysis is : 42.1% Na, 18.9% P, 39% of O. Find the empirical formula of the compound.
[H =1, N =14, Na = 23, P = 31, Cl = 35.5, Pt = 195]

Short/Brief Note
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Solution

Element Atomic mass Percentage Relative ratio of  moles Simplest mole ratio Whole number ratio
Na 23 42.1 42.1/23 = 1.8 1.8/0.6 =3 3
P 31 18.9 18.9/31 = 0.6 0.6/0.6
= 1
O 16 39

39/16
= 2.4

2.4/0.6 = 4 4

Empirical formula = Na3PO4.

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Chapter 5: Mole Concept and Stoichiometry - Questions from ICSE Examinations [Page 115]

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Frank Chemistry Part 2 [English] Class 10 ICSE
Chapter 5 Mole Concept and Stoichiometry
Questions from ICSE Examinations | Q 2002. 3. | Page 115

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