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Question
The output of the given circuit in figure is given below.
Options
would be zero at all times.
would be like a half wave rectifier with positive cycles in output.
would be like a half wave rectifier with negative cycles in output.
would be like that of a full wave rectifier.
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Solution
Would be like a half-wave rectifier with negative cycles in output.
Explanation:
(i) During the positive half cycle,
Diode → forward biased
Output signal → obtained
(ii) During the negative half cycle,
Diode → reverse biased
Output signal → not obtained
(iii) Output voltage is obtained across the load resistance R1. It is not constant but pulsating (mixture of ac and dc) in nature.
(iv) Average output in one cycle
(v) r.m.s output: `I_(rms) = I_0/2, V_(rms) = V_0/2`
When the diode is forward-biased during the positive half cycle of input AC voltage, the resistance of the p-n junction is low. The current in the circuit is maximum. In this situation, a maximum potential difference will appear across resistance connected in a series of circuits. This result in zero output voltage across the p-n junction.
And when the diode is reverse biased during the negative half cycle of AC voltage, the p-n junction is reverse biased. The resistance of the p-n junction becomes high which will be more than resistance in series. That is why there will be the voltage across p-n junction with a negative cycle in output,
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