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The outer dimensions of a wooden box are 20 cm, 12 cm and 8 cm. The thickness of the wood is 10 mm. Find (i) the volume of wood and (ii) the cost of the wood required for the box if 1 cm^3 of wood - Mathematics

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Question

The outer dimensions of a wooden box are 20 cm, 12 cm and 8 cm. The thickness of the wood is 10 mm. Find (i) the volume of wood and (ii) the cost of the wood required for the box if 1 cm3 of wood costs ₹ 8.50.

Sum
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Solution

Given:

  • Outer dimensions of the wooden box:
    • Length L = 20 cm
    • Width W = 12 cm
    • Height H = 8 cm
  • Thickness of the wood: 10 mm = 1 cm
  • Cost of wood: ₹ 8.50 per cm3

Step 1: Calculate the volume of the wood

We will find the volume of wood by subtracting the volume of the inner box from the volume of the outer box.

1. Outer volume of the box:

The outer dimensions of the box are given, so the volume of the outer box is:

Outer volume = L × W × H

 = 20 × 12 × 8

= 1,920 cm3

2. Inner dimensions of the box:

Since the thickness of the wood is 1 cm, the inner dimensions of the box will be reduced by 2 cm in each direction (1 cm on each side). 

  • Inner length = 20 – 2 = 18 cm 
  • Inner width = 12 – 2 = 10 cm 
  • Inner height = 8 – 2 = 6 cm 

3. Inner volume of the box:

The inner volume of the box is:

Inner volume = 18 × 10 × 6 = 1,080 cm3

4. Volume of the wood: 

The volume of the wood is the difference between the outer volume and the inner volume:

Volume of wood = Outer volume – Inner volume

= 1,920 cm3 – 1,080 cm3

= 840 cm3

Step 2: Calculate the cost of the wood

Now, we will calculate the cost of the wood based on the volume of the wood and the given cost per cm3.

Cost of the wood = Volume of wood × Cost per cm3

Cost of the wood = 840 cm3 × 8.50 = ₹ 7,140

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Chapter 18: Surface Area and Volume of Solids - MISCELLANEOUS EXERCISE [Page 226]

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B Nirmala Shastry Mathematics [English] Class 9 ICSE
Chapter 18 Surface Area and Volume of Solids
MISCELLANEOUS EXERCISE | Q 3. | Page 226
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