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ABCD is the cross-section of a metal container in a paint factory. If AB = 2.4 m, DC = 1.6 m, BQ = CR = 1.2 m, height of the container is 1.1 m. Find the volume of paint in the container. - Mathematics

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Question

ABCD is the cross-section of a metal container in a paint factory. If AB = 2.4 m, DC = 1.6 m, BQ = CR = 1.2 m, height of the container is 1.1 m. Find the volume of paint in the container.

Sum
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Solution

We have,

ABCD is the cross-section of a metal container in a paint factory. if AB = 2.4 m, DC = 1.6 m, BQ = CR = 1.2 m and height of the container is 1.1 m,


Area of cross-section ABCD is `1/2 (AB + DC) xx CM`

= `1/2 (1.6 + 2.4) xx 1.1`

= 2.2 m2

Now the volume of paint in the container 

= Area of cross-section × Length of metal container

= 2.2 × 1.2

= 2.64 m3

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Chapter 18: Surface Area and Volume of Solids - MISCELLANEOUS EXERCISE [Page 226]

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B Nirmala Shastry Mathematics [English] Class 9 ICSE
Chapter 18 Surface Area and Volume of Solids
MISCELLANEOUS EXERCISE | Q 2. | Page 226
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