Advertisements
Advertisements
Question
The number of students of Std 6th and Std 7th who went to visit the Tadoba Tiger Project at Chandrapur was 140 and 196 respectively. The students of each class are to be divided into groups of the same number of students. Each group can have a paid guide. What is the maximum number of students there can be in each group ? Why do you think each group should have the maximum possible number of students?
Advertisements
Solution
Number of students of Std 6th = 140
Number of students of Std 7th = 196
The maximum same number of students of each class that can be divided into each group is the HCF of 140 and 196.
Factors of 140: 1, 2, 4, 5, 7, 10, 14, 20, 28, 35, 70, 140
Factors of 196: 1, 2, 4, 7, 14, 28, 49, 98, 196
Common factors of 140 and 196: 1, 2, 4, 7, 14, 28
HCF of 140 and 196 = 28
∴ Maximum same number of students of each class that can be divided into each group = 28
Thus, the maximum number of students that can be in each group is 28.
Each group should have the maximum possible number of students so as to minimize the total amount paid to the guides.
RELATED QUESTIONS
Find the HCF:
16, 27
Find the HCF:
42, 45, 48
Find the prime factor of the following numbers and find their LCM and HCF.
32, 24, 48
Find the HCF and LCM of:
117, 221
Find the HCF and LCM of
2923, 3239
The product of two numbers is 2160 and their LCM is 320. Find their HCF.
Find the HCF set of numbers using prime factorisation method.
27, 45, 81
HCF of co-prime numbers 4 and 15 was found as follows by factorization:
4 = 2 × 2 and 15 = 3 × 5 since there is no common prime factor, so HCF of 4 and 15 is 0. Is the answer correct? If not, what is the correct HCF?
If the HCF of two numbers is 6, which of the following is definitely true?
The HCF of 10, 15 and 12 is 1. What does this imply?
