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Question
Find the HCF set of numbers using prime factorisation method.
45, 55, 95
Sum
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Solution
45, 55, 95
Prime factorisation of 45 = 3 × 3 × 5
Prime factorisation of 55 = 5 × 11
Prime factorisation of 95 = 5 × 19
Common factors of 45, 55, 95 = 5
HCF (45, 55, 95) = 5
| 3 | 45 |
| 3 | 15 |
| 5 | 5 |
| 1 |
| 5 | 55 |
| 11 | 11 |
| 1 |
| 5 | 95 |
| 19 | 19 |
| 1 |
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