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The metal salt A is blue in colour. When salt A is heated strongly over a burner, then a substance B is eliminated and a white powder C is left behind. When a few drops of a liquid D are added to

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Question

The metal salt A is blue in colour. When salt A is heated strongly over a burner, then a substance B is eliminated and a white powder C is left behind. When a few drops of a liquid D are added to powder C, it becomes blue again. What could be A, B, C and D?

Short Answer
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Solution

Copper sulphate crystals (A) are blue and have the chemical formula CuSO4.5H2O. When copper sulphate crystals are heated strongly, they lose all the water of crystallisation (B) and form anhydrous copper sulphate (C), which is white.

\[\ce{CuSO4 * 5H2O -> CuSO4 + 5H2O}\]

Anhydrous copper sulphate turns blue when a few drops of water are added (D) because it rehydrates.

\[\ce{CuSO4 + 5H2O -> CuSO4 * 5H2O}\]

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Chapter 2: Acids, Bases and Salts - Exercise 3 [Page 124]

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Lakhmir Singh Chemistry [English] Class 10
Chapter 2 Acids, Bases and Salts
Exercise 3 | Q 70. | Page 124
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