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Question
The magnetic field through a single loop of wire, 12 cm in radius and 8·5 Ω resistance, changes with time as shown in graph below. The magnetic field is perpendicular to the plane of the loop.
- Find the induced emf for the time intervals 0 to 2.0 s, 2.0 to 4.0 s, and 4.0 to 6.0 s.
- Hence, plot induced current as a function of time.

Numerical
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Solution
(a) e = `−("d"phi)/("dt")`
= `-("dNAB" costheta)/("dt")`
e = −0.023 volt
i = `"e"/"R"`
= `- 0.023/8.5`
= −2.7 × 10-3 A
t : 0 −2.0 sec : i = −2.7 × 10-3 A
t : 2.0 sec −4.0 sec : i = 0
t : 4.0 sec −6.0 sec : i = +2.7 × 10-3 A
(b)

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Magnetic Field Intensity Due to a Magnetic Dipole (Bar Magnet) Perpendicular to Its Axis
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