Advertisements
Advertisements
प्रश्न
The magnetic field through a single loop of wire, 12 cm in radius and 8·5 Ω resistance, changes with time as shown in graph below. The magnetic field is perpendicular to the plane of the loop.
- Find the induced emf for the time intervals 0 to 2.0 s, 2.0 to 4.0 s, and 4.0 to 6.0 s.
- Hence, plot induced current as a function of time.

संख्यात्मक
Advertisements
उत्तर
(a) e = `−("d"phi)/("dt")`
= `-("dNAB" costheta)/("dt")`
e = −0.023 volt
i = `"e"/"R"`
= `- 0.023/8.5`
= −2.7 × 10-3 A
t : 0 −2.0 sec : i = −2.7 × 10-3 A
t : 2.0 sec −4.0 sec : i = 0
t : 4.0 sec −6.0 sec : i = +2.7 × 10-3 A
(b)

shaalaa.com
Magnetic Field Intensity Due to a Magnetic Dipole (Bar Magnet) Perpendicular to Its Axis
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
