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The loss per cent on selling 140 geometry boxes at the loss of S.P. of 10 geometry boxes is equal to ______.

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Question

The loss per cent on selling 140 geometry boxes at the loss of S.P. of 10 geometry boxes is equal to ______.

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Solution

The loss per cent on selling 140 geometry boxes at the loss of S.P. of 10 geometry boxes is equal to `underlinebb(6 2/3 %)`.

Explanation:

Let the selling price of 1 geometry box be Rs. 1.

So, the selling price for 140 geometry boxes = Rs. 1 × 140 = Rs. 140

Similarly, selling price of 10 geometry boxes = Rs. 1 × 10 = Rs. 10

Loss = Selling price of 10 geometry boxes = Rs. 10

∴ Loss percentage = `"Loss"/"CP" xx 100`

= `10/(140 + 10) xx 100`

= `10/150 xx 100`

= `20/3`%

= `6 2/3`%

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Chapter 9: Comparing Quantities - Exercise [Page 291]

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NCERT Exemplar Mathematics Exemplar [English] Class 8
Chapter 9 Comparing Quantities
Exercise | Q 39. | Page 291

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