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प्रश्न
The loss per cent on selling 140 geometry boxes at the loss of S.P. of 10 geometry boxes is equal to ______.
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उत्तर
The loss per cent on selling 140 geometry boxes at the loss of S.P. of 10 geometry boxes is equal to `underlinebb(6 2/3 %)`.
Explanation:
Let the selling price of 1 geometry box be Rs. 1.
So, the selling price for 140 geometry boxes = Rs. 1 × 140 = Rs. 140
Similarly, selling price of 10 geometry boxes = Rs. 1 × 10 = Rs. 10
Loss = Selling price of 10 geometry boxes = Rs. 10
∴ Loss percentage = `"Loss"/"CP" xx 100`
= `10/(140 + 10) xx 100`
= `10/150 xx 100`
= `20/3`%
= `6 2/3`%
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A mixer grinder marked at ₹ 4500 is sold for ₹ 4140 after discount. The rate of discount is __________
Fill up the appropriate boxes in the following table.
| SI. No | C.P. in ₹ |
M.P. in ₹ |
S.P. in ₹ |
Discount in ₹ |
Profit in ₹ |
Loss in ₹ |
| (i) | 110 | 130 | Nil | |||
| (ii) | 110 | 130 | 10 | |||
| (iii) | 110 | 130 | 30 | |||
| (iv) | 110 | 120 | Nil | 10 | ||
| (v) | 120 | 10 | 20 | Nil |
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