Question

A dealer bought two tables for Rs 3120. He sold one of them at a loss of 15% and other at a gain of 36%. Then, he found that each table was sold for the same price. Find the cost price of each table.

Answer 1

\[\text { Given that the selling price is same for both the tables } . \]

\[\text { Let the C . P of 1 table be Rs . x, then the C . P of the other will be Rs } . \left( 3120 - x \right) . \]

\[\text { Loss on the first table = 15 % } \]

\[\text { Therefore, S . P = C . P }\left( \frac{100 -\text {  loss % }}{100} \right)\]

\[ S . P = \frac{85x}{100} = Rs . 0 . 85x\]

\[\text { Gain on the second table = 36 % } \]

\[\text { Therefore, S . P = C . P }\left( \frac{100 + \text { gain % }}{100} \right)\]

\[\text { S . P = Rs . 1 . 36 }\left( 3120 - x \right)\]

\[\text { Since both tables have the same S . P }, \]

\[\text { So,} 0 . 85x = 1 . 36\left( 3120 - x \right)\]

\[0 . 85x = 4243 . 20 - 1 . 36x\]

\[2 . 21x = 4243 . 20\]

\[ x = \frac{4243 . 20}{2 . 21}\]

\[ x = Rs . 1920\]

\[\text { So, the cost price of the first table is Rs } . 1920 . \]

\[\text { Cost price of the second table = Rs }. ( 3120 - 1920) = Rs . 1200\]