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प्रश्न
A dealer bought two tables for Rs 3120. He sold one of them at a loss of 15% and other at a gain of 36%. Then, he found that each table was sold for the same price. Find the cost price of each table.
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उत्तर
\[\text { Given that the selling price is same for both the tables } . \]
\[\text { Let the C . P of 1 table be Rs . x, then the C . P of the other will be Rs } . \left( 3120 - x \right) . \]
\[\text { Loss on the first table = 15 % } \]
\[\text { Therefore, S . P = C . P }\left( \frac{100 -\text { loss % }}{100} \right)\]
\[ S . P = \frac{85x}{100} = Rs . 0 . 85x\]
\[\text { Gain on the second table = 36 % } \]
\[\text { Therefore, S . P = C . P }\left( \frac{100 + \text { gain % }}{100} \right)\]
\[\text { S . P = Rs . 1 . 36 }\left( 3120 - x \right)\]
\[\text { Since both tables have the same S . P }, \]
\[\text { So,} 0 . 85x = 1 . 36\left( 3120 - x \right)\]
\[0 . 85x = 4243 . 20 - 1 . 36x\]
\[2 . 21x = 4243 . 20\]
\[ x = \frac{4243 . 20}{2 . 21}\]
\[ x = Rs . 1920\]
\[\text { So, the cost price of the first table is Rs } . 1920 . \]
\[\text { Cost price of the second table = Rs }. ( 3120 - 1920) = Rs . 1200\]
संबंधित प्रश्न
A shopkeeper buys 80 articles for Rs 2,400 and sells them for a profit of 16%. Find the selling price of one article.
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If the profit earned on selling an article for ₹ 810 is the same as loss on selling it for ₹ 530, then find the cost price of the article.
Fill up the appropriate boxes in the following table
| SI. No | C.P. in ₹ |
S.P. in ₹ |
Profit in ₹ |
Loss in ₹ |
| (i) | 100 | 120 | ||
| (ii) | 110 | 120 | ||
| (iii) | 120 | 20 | ||
| (iv) | 100 | 90 | ||
| (v) | 120 | 25 |
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| Item | Price of each | Number of items | Cost |
| Borewell for freshwater | Rs 3000 | 1 | |
| Bamboo rack for fish drying | Rs 2000 | 20 | |
| Cement tank | Rs 1000 | 4 | |
| Tray and knife | Rs 300 | 20 | |
| Bucket | Rs 75 | 20 |
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In one month they plan to dry 6000 kg of fresh fish.
How much-dried fish will they get in a month?
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