Question

The force of attraction between two bodies at certain separation is 10 N. What will be the force of attraction between them if the separation is reduced to half? 

Answer 1

Given the force of attraction between two bodies = 10 N

Now , `"F" = "G"("Mm")/"R"^2` .

If the new distance R'= R/2, then let F' be the force acting between the bodies. Then:

`F' = "G"("Mm")/(R"/"2)^2 = 4G(Mm)/R^2`

or , F' = 4F

or , F' = 4 × 10 = 40N