Advertisements
Advertisements
प्रश्न
The force of attraction between two bodies at certain separation is 10 N. What will be the force of attraction between them if the separation is reduced to half?
Advertisements
उत्तर
Given the force of attraction between two bodies = 10 N
Now , `"F" = "G"("Mm")/"R"^2` .
If the new distance R'= R/2, then let F' be the force acting between the bodies. Then:
`F' = "G"("Mm")/(R"/"2)^2 = 4G(Mm)/R^2`
or , F' = 4F
or , F' = 4 × 10 = 40N
APPEARS IN
संबंधित प्रश्न
Define gravitational constant G.
Explain the following:
Why does a boatman push the bank backward with a long bamboo pole, on launching his boat in the water?
State unit of mass in CGS system.
Define momentum of a body.
What is the ratio of SI units to CGS units of momentum?
Why do passengers tend to fall sideways when the bus takes a sharp turn?
Why do passengers tend to fall backward when it starts suddenly?
Why do the dust particles come out of a hanging carpet when it is beaten with a stick?
Why is a tree shaken to get its fruit down?
What is the relation between Newton and dyne?
