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प्रश्न
The force of attraction between two bodies at certain separation is 10 N. What will be the force of attraction between them if the separation is reduced to half?
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उत्तर
Given the force of attraction between two bodies = 10 N
Now , `"F" = "G"("Mm")/"R"^2` .
If the new distance R'= R/2, then let F' be the force acting between the bodies. Then:
`F' = "G"("Mm")/(R"/"2)^2 = 4G(Mm)/R^2`
or , F' = 4F
or , F' = 4 × 10 = 40N
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