Question

The floor of a room is 8 m 96 cm long and 6 m 72 cm broad. Find the minimum number of square tiles of the same size needed to cover the entire floor.

Answer 1

Length of floor of a room = 8 m 96 cm = 896 cm

Breadth of floor of the room = 6 m 72 cm = 672 cm

To find the minimum number of square tiles of same size needed to cover the entire floor, we find the LCM of 896 cm and 672 cm.

2	672, 896
2	336, 448
2	168, 224
2	84, 112
2	42, 56
2	21, 28
2	21, 14
3	21, 7
7	7, 7
	1, 1

∴ LCM of 672 and 896 is 2 × 2 × 2 × 2 × 2 × 2 × 2 × 3 × 7 = 2688

∴ Number of square tiles = `(2688/672 xx 2688/896)`

= 4 × 3 

= 12