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Three brands A, B and C of biscuits are available in packets of 12, 15 and 21 biscuits respectively. If a shopkeepeer wants to buy an equal number of biscuits, of each brand - Mathematics

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Question

Three brands A, B and C of biscuits are available in packets of 12, 15 and 21 biscuits respectively. If a shopkeepeer wants to buy an equal number of biscuits, of each brand, what is the minimum number of packets of each brand, he should buy?

Sum
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Solution

A shopkeeper has three brands A, B and C of biscuits are available in packets of 12, 15 and 21 biscuits respectively.

Also, a shopkeeper wants to buy equal number of biscuits of each brand for that we need to find the LCM of 12, 15 and 21.

2 12, 15, 21
2 6, 15, 21
3 3, 15, 21
5 1, 5, 7
7 1, 1, 7
  1, 1, 1

∴ The LCM of 12, 15 and 21

= 2 × 2 × 3 × 5 × 7

= 420 

Thus, the required number of packets of 420.

Brand A = `420/12` = 35

Brand B = `420/15` = 28

Brand C = `420/21` = 20

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Chapter 1: Number System - Exercise [Page 20]

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NCERT Exemplar Mathematics [English] Class 6
Chapter 1 Number System
Exercise | Q 194. | Page 20
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