Question

The first three terms of an A.P. are $$3y - 1, 3y + 5$$ and $$5y + 1$$ respectively. Then, the value of $$y$$ is ______.

Options

• $$1$$

• $$5$$

• $$8$$

• $$3$$

Answer 1

The first three terms of an A.P. are $$3y - 1, 3y + 5$$ and $$5y + 1$$ respectively. Then, the value of $$y$$ is 5.

Explanation:

For an A.P., $$2(3y + 5) = (3y - 1) + (5y + 1)$$, giving $$6y + 10 = 8y$$ and $$y = 5$$.