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Question
The equation of the circle which passes through the point (4, 5) and has its centre at (2, 2) is ______.
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Solution
The equation of the circle which passes through the point (4, 5) and has its centre at (2, 2) is (x – 2)2 + (y – 2)2 = 13.
Explanation:
As the circle is passing through the point (4, 5) and its centre is (2, 2)
So its radius is `sqrt((4 - 2)^2 + (5 - 2)^2) = sqrt(13)`
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