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Tamil Nadu Board of Secondary EducationHSC Science Class 12

The electrostatic potential is given as a function of x in figure (a) and (b). Calculate the corresponding electric fields in regions A, B, C and D. Plot the electric field as a function of - Physics

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Question

The electrostatic potential is given as a function of x in figure (a) and (b). Calculate the corresponding electric fields in regions A, B, C and D. Plot the electric field as a function of x for figure (b).



Numerical
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Solution

Figure a:

`vec"E" = - "dv"/"dx" hat"i"`

From 0 to 0.2 m,

`"E"_"x" = "dv"/"dx" = 3/0.2 = 30/2 = 15`Vm-1 (region A)

`"E"_"x" = "dv"/"dx"` = 0 

Since the potential is constant (region B)

`"E"_"x" = "dv"/"dx" = (-2)/0.2 = (-20)/2` = - 10 Vm-1 (region c) 

`"E"_"x" = "dv"/"dx" = 6/0.2 = 60/2` = 30 Vm-1 (region d)

Figure b:

`"E"_"x" = "dv"/"dx"` = - 30 Vm-1 (region 0-1 cm)

`"E"_"x" = "dv"/"dx"` = 30 Vm-1 (region 1-2 cm)

`"E"_"x" = "dv"/"dx"` = 0   (region 2-3 cm)

`"E"_"x" = "dv"/"dx"` = 30 Vm-1 (region 3-4 cm)

`"E"_"x" = "dv"/"dx"` = - 30 Vm-1 (region 4-5 cm)

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Electrostatic Potential and Potential Energy
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Chapter 1: Electrostatics - Evaluation [Page 76]

APPEARS IN

Samacheer Kalvi Physics - Volume 1 and 2 [English] Class 12 TN Board
Chapter 1 Electrostatics
Evaluation | Q 8. | Page 76
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