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The electric potential at any point on the equatorial line of a dipole (θ = 90°) is:

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Question

The electric potential at any point on the equatorial line of a dipole (θ = 90°) is:

Options

  • \[V = \frac{p}{4\pi\varepsilon_0 r}\]

  • \[V = \frac{p}{4\pi\varepsilon_0 r^2}\]

  • \[V = 0\]

  • \[V = \frac{2p}{4\pi\varepsilon_0 r^2}\]

MCQ
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Solution

At an equatorial point, θ = 90°, so cos θ = 0. Substituting into V = p cos θ/(4πε₀r²) gives V = 0; every point on the equatorial line is at zero potential.

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