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Question
The displacement of a particle at time t is given by s = 2t3 – 5t2 + 4t – 3. Find the velocity when 𝑡 = 2 sec
Sum
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Solution
s = 2t3 – 5t2 + 4t – 3
∴ v = `("ds")/("dt")`
= 6t2 – 10t + 4
`"v"_(("t" = 2))` = 6(2)2 – 10(2) + 4
= 24 – 20 + 4
= 8 units/sec
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