Question

The displacement of a particle at time t is given by s = 2t³ – 5t² + 4t – 3. Find the velocity when 𝑡 = 2 sec

Answer 1

s = 2t³ – 5t² + 4t – 3

∴ v = `("ds")/("dt")`

= 6t² – 10t + 4

`"v"_(("t" = 2))` = 6(2)² – 10(2) + 4

= 24 – 20 + 4

= 8 units/sec