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The dimensions of a room are 14 m × 10 m × 6.5 m. There are two doors and 4 windows in the room. Each door measures 2.5 m × 1.2 m and each window measures 15 m × 1 m.

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Question

The dimensions of a room are 14 m × 10 m × 6.5 m. There are two doors and 4 windows in the room. Each door measures 2.5 m × 1.2 m and each window measures 15 m × 1 m. Find the cost of painting the four walls of the room at ₹ 35 per m2.

Sum
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Solution

The room has four walls to be painted 

Area of these walls=`2(lxxh)+2(bxxh)` 

=`(2xx14xx6.5)+(2xx10xx6.5)` 

=`312m^2` 

Now, Area of the two doors=`(2xx2.5xx1.2)=6m^2` 

Area of the four windows=`(4xx1.5xx1)=6m^2` 

The walls have to be painted; the doors and windows are not to be painted. 

∴ Total area to be painted =`312-(6+6)=300m^2` 

Cost for painting=`1m^2=Rs35` 

Cost for painting `300m^2=300xx35=Rs10,500`

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Chapter 15: Perimeter And Area of Plane Figures - EXERCISE 15B [Page 693]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 15 Perimeter And Area of Plane Figures
EXERCISE 15B | Q 17. | Page 693
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