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The diameter of the moon is approximately one-fourth of the diameter of the earth. Find the ratio of their surface area.

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Question

The diameter of the moon is approximately one-fourth of the diameter of the earth. Find the ratio of their surface area.

Sum
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Solution

Let the diameter of earth be d. Therefore, the diameter of the moon will be `d/4`.

Radius of earth = `d/2`

Radius of moon = `1/2xxd/4 = d/8`

Surface area of moon = `4pi(d/8)^2`

Surface area of earth = `4pi(d/2)^2`

Required ratio = `(4pi(d/8)^2)/(4pi(d/2)^2)=4/64=1/16`

Therefore, the ratio between their surface areas will be 1 : 16.

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Chapter 11: Surface Area and Volumes - EXERCISE 11.2 [Page 145]

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NCERT Mathematics [English] Class 9
Chapter 11 Surface Area and Volumes
EXERCISE 11.2 | Q 7. | Page 145

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