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Question
From a rectangular solid of metal 42 cm by 30 cm by 20 cm, a conical cavity of diameter 14 cm and depth 24 cm is drilled out. Find: the volume of remaining solid
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Solution
Dimensions of rectangular solids = `=(42xx30xx20) "cm"`
volume=`(42xx30xx20)=25200 "cm"^3 `
Radius of conical cavity (r) =7 cm
height (h)=24 cm
Volume of cone=`1/3pir^2h`
=`1/3xx22/7xx7xx7xx24`
`= 1232 "cm"^3`
Volume of remaining solid =` (25200-1232)=23968 "cm"^3`
Radius of conical cavity (r) =7 cm
height (h) = 24 cm
Volume of cone = `1/3 pi "r"^2"h"`
`= 1/3 xx 22/7 xx 7 xx 7 xx 24`
= 1232 cm3
Volume of remaining solid = (25200 - 1232) = 23968 cm3
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