English

The diagram above is a schematic diagram of a household circuit. The house shown in the above diagram has 5 usable spaces where electrical connections are made.

Advertisements
Advertisements

Question

The diagram above is a schematic diagram of a household circuit. The house shown in the above diagram has 5 usable spaces where electrical connections are made. For this house, the mains have a voltage of 220 V and the net current coming from the mains is 22A.

  1. What is the mode of connection to all the spaces in the house from the mains?
  2. The spaces 5 and 4 have the same resistance and spaces 3 and 2 have respective resistances of 20Ω and 30Ω. Space 1 has a resistance double that of space 5. What is the net resistance for space 5.
  3. What is the current in space 3?
  4. What should be placed between the main connection and the rest of the house’s electrical appliances to save them from accidental high electric current?
Answer in Brief
Advertisements

Solution

(a) All spaces are connected in parallel.

(b) Let Resistance of Space 5 and 4 be R ohms respectively

Resistance of Space 1 = 2 R ohms

Resistance of Space 2 = 30 ohms

Resistance of Space 3 = 20 ohms

Current = 22 A

V = 220 V

Total Resistance = `"V"/"I"`

 `1/("R"_1) + 1/("R"_2) + 1/("R"_3) + 1/("R"_4) + 1/("R"_5) = 1/("R"_("eq"))`

 `1/(2 "R") + 1/30 + 1/20 + 1/"R" + 1/"R" = 1/("R"_("eq"))` 

 `(30 + 2"R" + 3"R" + 60 + 60)/(60 "R") =  1/("R"_("eq"))`

`(150 + 5"R")/(60"R") = 1/("R"_("eq"))`

`"R"_("eq") = (60"R")/(150 + 5"R") = cancel(220)^10/cancel(22)_1`

60 R = 10 (150 + 5R)

60 R = 1500 + 50 R

10 R = 1500

R = 150 Ω  

(c) `"I"_3 = "V"/"R"_3`

= `220/20`

= 11A

(d) Electrical Fuses/Mcbs should be placed between the main connection and the rest of the house's electrical appliances to save them from sudden surges in electric current.

shaalaa.com
  Is there an error in this question or solution?
2022-2023 (March) Sample

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

An electric heater which is connected to a 220 V supply line has two resistance coils A and B of 24 Ω resistance each. These coils can be used separately (one at a time), in series or in parallel. Calculate the current drawn when:

(a) only one coil A is used.
(b) coils A and B are used in series.
(c) coils A and B are uses in parallel.


A 4 Ω coil and a 2 Ω coil are connected in parallel. What is their combined resistance? A total current of 3 A passes through the coils. What current passes through the 2 Ω coil? 


A wire of resistance R1 is cut into five equal pieces. These five pieces of wire are then connected in parallel. If the resultant resistance of this combination be R2, then the ratio `R_1/R_2` is: 

(a) `1/25`

(b)1/5

(c)5

(c)25


What are the advantages of a parallel connection?


How does the resistance of a metallic wire depend on the length of wire?


Two devices are connected between two points say A and B in parallel. The physical quantity that will remain the same between the two points is:


Three resistors of 1 Ω, 2 Ω and 3 Ω are connected in parallel. The combined resistance of the three resistors should be:


Assertion: When a battery is short circuited, the terminal voltage is zero.

Reason: In a short circuit, the current is zero.


A piece of wire of resistance R is cut into three equal parts. These parts are then connected in parallel. If the equivalent resistance of this parallel combination is R1, what is the value of the ratio R1 : R?


You have three resistors of values 2 Ω, 3 Ω, and 5 Ω. How will you join them so that the total resistance is less than 1 Ω? Draw a diagram and find the total resistance.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×