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Question
The diagonals of a rhombus are 48 cm and 20 cm long. Find the perimeter of the rhombus.
Sum
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Solution
Given: Diagonals d1 = 48 cm, d2 = 20 cm.
The diagonals of a rhombus bisect each other at right angles, so half-lengths are 24 cm and 10 cm.
Using Pythagoras on one half-triangle:
`AB = sqrt(24^2 + 10^2)`
= `sqrt(576 + 100)`
= `sqrt(676)`
= 26 cm
Therefore perimeter = 4 × 26
= 104 cm
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