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The current sensitivity of a moving coil galvanometer is given by:

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Question

The current sensitivity of a moving coil galvanometer is given by:

Options

  • \[\frac{\phi}{V}=\frac{NAB}{CG}\]

  • \[\frac{\phi}{I}=\frac{NAB}{C}\]

  • \[\frac{V}{I_g}-G\]

  • \[\frac{I}{\phi}=\frac{C}{NAB}\]

MCQ
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Solution

Current sensitivity is \[CS = \frac{\phi}{I} = \frac{NAB}{C}\] where \(N\) is the number of turns, \(A\) the coil area, \(B\) the magnetic field, and \(C\) the torsional constant of the spring. It increases with \(N\), \(A\), \(B\) and decreases with larger \(C\).

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