Advertisements
Advertisements
Question
The current sensitivity of a moving coil galvanometer is given by:
Options
\[\frac{\phi}{V}=\frac{NAB}{CG}\]
\[\frac{\phi}{I}=\frac{NAB}{C}\]
\[\frac{V}{I_g}-G\]
\[\frac{I}{\phi}=\frac{C}{NAB}\]
MCQ
Advertisements
Solution
Current sensitivity is \[CS = \frac{\phi}{I} = \frac{NAB}{C}\] where \(N\) is the number of turns, \(A\) the coil area, \(B\) the magnetic field, and \(C\) the torsional constant of the spring. It increases with \(N\), \(A\), \(B\) and decreases with larger \(C\).
shaalaa.com
Is there an error in this question or solution?
