Question

The current sensitivity of a moving coil galvanometer is given by:

पर्याय

• \[\frac{\phi}{V}=\frac{NAB}{CG}\]

• \[\frac{\phi}{I}=\frac{NAB}{C}\]

• \[\frac{V}{I_g}-G\]

• \[\frac{I}{\phi}=\frac{C}{NAB}\]

Answer 1

Current sensitivity is \[CS = \frac{\phi}{I} = \frac{NAB}{C}\] where \(N\) is the number of turns, \(A\) the coil area, \(B\) the magnetic field, and \(C\) the torsional constant of the spring. It increases with \(N\), \(A\), \(B\) and decreases with larger \(C\).