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The corner points of the feasible region of a linear programming problem are (0, 4), (8, 0) and (203,43). If Z = 30x + 24y is the objective function, then (maximum value of Z – minimum value of Z)

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Question

The corner points of the feasible region of a linear programming problem are (0, 4), (8, 0) and `(20/3, 4/3)`. If Z = 30x + 24y is the objective function, then (maximum value of Z – minimum value of Z) is equal to ______.

Options

  • 40

  • 96

  • 120

  • 136

  • 144

MCQ
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Solution

The corner points of the feasible region of a linear programming problem are (0, 4), (8, 0) and `(20/3, 4/3)`. If Z = 30x + 24y is the objective function, then (maximum value of Z – minimum value of Z) is equal to 144.

Explanation:

Corner Points Z = 30x + 24y
(0, 4) Z = 30 × 0 + 24 × 4 = 96 `rightarrow` Min.
(8, 0) Z = 30 × 8 + 24 × 0 = 240 `rightarrow` Max.
`(20/3, 4/3)`

Z = `30 xx 20/3 + 24 xx 4/3` = 200 + 32 = 232

Then Max. Z – Min. Z = 240 – 96 = 144.

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