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The coordination number and the oxidation state of the element ‘E’ in the complex [E(en)2(C2O4)]NO2 (where (en) is ethylenediamine) are, respectively ______. - Chemistry (Theory)

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Question

The coordination number and the oxidation state of the element ‘E’ in the complex [E(en)2(C2O4)]NO2 (where (en) is ethylenediamine) are, respectively ______.

Options

  • 6 and 2

  • 4 and 2

  • 4 and 3

  • 6 and 3

MCQ
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Solution

The coordination number and the oxidation state of the element ‘E’ in the complex [E(en)2(C2O4)]NO2 (where (en) is ethylenediamine) are, respectively 6 and 3.

Explanation:

  • Ethylenediamine (en) and oxalate (C2O4) are bidentate ligands, contributing 4 and 2 coordination sites, respectively. Therefore, the coordination number is 6.
  • NO2 is a neutral counterion, and the ligands are neutral, so the oxidation state of E is +3 to balance the charge.
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Chapter 9: Coordination Compounds - OBJECTIVE (MULTIPLE CHOICE) TYPE QUESTIONS [Page 550]

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Nootan Chemistry Part 1 and 2 [English] Class 12 ISC
Chapter 9 Coordination Compounds
OBJECTIVE (MULTIPLE CHOICE) TYPE QUESTIONS | Q 46. | Page 550
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