हिंदी

The coordination number and the oxidation state of the element ‘E’ in the complex [E(en)2(C2O4)]NO2 (where (en) is ethylenediamine) are, respectively ______. - Chemistry (Theory)

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प्रश्न

The coordination number and the oxidation state of the element ‘E’ in the complex [E(en)2(C2O4)]NO2 (where (en) is ethylenediamine) are, respectively ______.

विकल्प

  • 6 and 2

  • 4 and 2

  • 4 and 3

  • 6 and 3

MCQ
रिक्त स्थान भरें
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उत्तर

The coordination number and the oxidation state of the element ‘E’ in the complex [E(en)2(C2O4)]NO2 (where (en) is ethylenediamine) are, respectively 6 and 3.

Explanation:

  • Ethylenediamine (en) and oxalate (C2O4) are bidentate ligands, contributing 4 and 2 coordination sites, respectively. Therefore, the coordination number is 6.
  • NO2 is a neutral counterion, and the ligands are neutral, so the oxidation state of E is +3 to balance the charge.
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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Coordination Compounds - OBJECTIVE (MULTIPLE CHOICE) TYPE QUESTIONS [पृष्ठ ५५०]

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नूतन Chemistry Part 1 and 2 [English] Class 12 ISC
अध्याय 9 Coordination Compounds
OBJECTIVE (MULTIPLE CHOICE) TYPE QUESTIONS | Q 46. | पृष्ठ ५५०
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