मराठी

The coordination number and the oxidation state of the element ‘E’ in the complex [E(en)2(C2O4)]NO2 (where (en) is ethylenediamine) are, respectively ______.

Advertisements
Advertisements

प्रश्न

The coordination number and the oxidation state of the element ‘E’ in the complex [E(en)2(C2O4)]NO2 (where (en) is ethylenediamine) are, respectively ______.

पर्याय

  • 6 and 2

  • 4 and 2

  • 4 and 3

  • 6 and 3

MCQ
रिकाम्या जागा भरा
Advertisements

उत्तर

The coordination number and the oxidation state of the element ‘E’ in the complex [E(en)2(C2O4)]NO2 (where (en) is ethylenediamine) are, respectively 6 and 3.

Explanation:

  • Ethylenediamine (en) and oxalate (C2O4) are bidentate ligands, contributing 4 and 2 coordination sites, respectively. Therefore, the coordination number is 6.
  • NO2 is a neutral counterion, and the ligands are neutral, so the oxidation state of E is +3 to balance the charge.
shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×