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प्रश्न
The coordination number and the oxidation state of the element ‘E’ in the complex [E(en)2(C2O4)]NO2 (where (en) is ethylenediamine) are, respectively ______.
पर्याय
6 and 2
4 and 2
4 and 3
6 and 3
MCQ
रिकाम्या जागा भरा
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उत्तर
The coordination number and the oxidation state of the element ‘E’ in the complex [E(en)2(C2O4)]NO2 (where (en) is ethylenediamine) are, respectively 6 and 3.
Explanation:
- Ethylenediamine (en) and oxalate (C2O4) are bidentate ligands, contributing 4 and 2 coordination sites, respectively. Therefore, the coordination number is 6.
- NO2 is a neutral counterion, and the ligands are neutral, so the oxidation state of E is +3 to balance the charge.
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