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Question
The composition of functions is commutative.
Options
True
False
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Solution
This statement is False.
Explanation:
Let f(x) = x2 and g(x) = x + 1
fog(x) = f((g(x))
= f(x + 1)
= (x + 1)2
= x2 + 2x + 1
gof(x) = g(f(x))
= g(x2)
= x2 + 1
Thus fog(x) ≠ gof(x)
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