English

If f: R → R be given by f(x) = (3 – x^3)^(1/3), then fof(x) is ______.

Advertisements
Advertisements

Question

If f: R → R be given by `f(x) = (3 - x^3)^(1/3)`, then fof(x) is ______.

Options

  • `1/(x^3)`

  • x3

  • x

  • (3 – x3)

MCQ
Fill in the Blanks
Advertisements

Solution

x

Explanation:

f: R → R is given as `f(x) = (3 - x^3)^(1/3)`

`f(x) = (3 - x^3)^(1/3)`

∴ fof(x) = f(f(x))

= `f((3 - x^3)^(1/3))`

= `[3 - ((3 - x^3)^(1/3))^3]^(1/3)`

= `[3 - (3 - x^3)]^(1/3)`

= `(x^3)^(1/3)`

= x

∴ fof(x) = x

shaalaa.com
  Is there an error in this question or solution?

RELATED QUESTIONS

Let f : W → W be defined as

`f(n)={(n-1, " if n is odd"),(n+1, "if n is even") :}`

Show that f is invertible a nd find the inverse of f. Here, W is the set of all whole
numbers.


Find gof and fog, if f(x) = 8x3 and `g(x) = x^(1/3)`.


State with reason whether following functions have inverse

f: {1, 2, 3, 4} → {10} with f = {(1, 10), (2, 10), (3, 10), (4, 10)}


Show that f: [–1, 1] → R, given by f(x) = `x/(x + 2)`  is one-one. Find the inverse of the function f: [–1, 1] → Range f.

(Hint: For y in Range f, y = `f(x) = x/(x + 2)` for some x in [–1, 1] i.e., `x = (2y)/(1 - y)`)


Consider f: R → R given by f(x) = 4x + 3. Show that f is invertible. Find the inverse of f.


Consider f: R→ [4, ∞) given by f(x) = x2 + 4. Show that f is invertible with the inverse f−1 of given f by `f^(-1)(y) = sqrt(y - 4)`, where R+ is the set of all non-negative real numbers.


Consider f: R+ → [–5, ∞) given by f(x) = 9x2 + 6x – 5. Show that f is invertible with `f^(-1)(y) = ((sqrt(y + 6) - 1)/3)`.


Let f: X → Y be an invertible function. Show that the inverse of f−1 is f, i.e., (f−1)−1 = f.


Let f: W → W be defined as f(n) = n − 1, if is odd and f(n) = n + 1, if n is even. Show that f is invertible. Find the inverse of f. Here, W is the set of all whole numbers.


If f : R → R, f(x) = x and g: R → R , g(x) =  2x+ 1, and R is the set of real numbers, then find fog(x) and gof (x)


Let f: R → R be defined by f(x) = 3x 2 – 5 and g: R → R by g(x) = `x/(x^2 + 1)` Then gof is ______.


Let f: A → B and g: B → C be the bijective functions. Then (g o f)–1 is ______.


Let f: [0, 1] → [0, 1] be defined by f(x) = `{{:(x",",  "if"  x  "is rational"),(1 - x",",  "if"  x  "is irrational"):}`. Then (f o f) x is ______.


Let f: N → R be the function defined by f(x) = `(2x - 1)/2` and g: Q → R be another function defined by g(x) = x + 2. Then (g o f) `3/2` is ______.


Let f = {(1, 2), (3, 5), (4, 1) and g = {(2, 3), (5, 1), (1, 3)}. Then g o f = ______ and f o g = ______.


The composition of functions is associative.


If f : R → R, g : R → R and h : R → R is such that f(x) = x2, g(x) = tanx and h(x) = logx, then the value of [ho(gof)](x), if x = `sqrtpi/2` will be ____________.


Let f : N → R : f(x) = `((2"x"−1))/2` and g : Q → R : g(x) = x + 2 be two functions. Then, (gof) `(3/2)` is ____________.


If f(x) = `(3"x" + 2)/(5"x" - 3)` then (fof)(x) is ____________.


If f(x) = (ax2 – b)3, then the function g such that f{g(x)} = g{f(x)} is given by ____________.


Which one of the following functions is not invertible?


The inverse of the function `"y" = (10^"x" - 10^-"x")/(10^"x" + 10^-"x")` is ____________.


If f : R → R defind by f(x) = `(2"x" - 7)/4` is an invertible function, then find f-1.


If f : R → R defined by f(x) `= (3"x" + 5)/2` is an invertible function, then find f-1.


A general election of Lok Sabha is a gigantic exercise. About 911 million people were eligible to vote and voter turnout was about 67%, the highest ever


Let I be the set of all citizens of India who were eligible to exercise their voting right in the general election held in 2019. A relation ‘R’ is defined on I as follows:

R = {(V1, V2) ∶ V1, V2 ∈ I and both use their voting right in the general election - 2019}

  • Two neighbors X and Y ∈ I. X exercised his voting right while Y did not cast her vote in a general election - 2019. Which of the following is true?

`f : x -> sqrt((3x^2 - 1)` and `g : x -> sin (x)` then `gof : x ->`?


The domain of definition of f(x) = log x2 – x + 1) (2x2 – 7x + 9) is:-


Domain of the function defined by `f(x) = 1/sqrt(sin^2 - x) log_10 (cos^-1 x)` is:-


If `f(x) = 1/(x - 1)`, `g(x) = 1/((x + 1)(x - 1))`, then the number of integers which are not in domian of gof(x) are


If f: A → B and G B → C are one – one, then g of A → C is


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×