Advertisements
Advertisements
Question
The circumference of a circular field is 308 m. Find is:
(i) Radius
(ii) Area.
Advertisements
Solution
Let r be the radius of the circular field
(i) 2πr = 308
⇒ r = `[308]/ [2π]`
⇒ r = `(308)/(2) xx (7)/(22)`
⇒ r = 49 m
(ii) area = πr2
= `22/7 xx ( 49 )^2`
= 7546 m2
APPEARS IN
RELATED QUESTIONS
All the vertices of a rhombus lie on a circle. Find the area of the rhombus, if the area of the circle is 1256 cm2. (Use π = 3.14)
In Fig. 6, find the area of the shaded region, enclosed between two concentric circles of radii 7 cm and 14 cm where ∠AOC = 40°. (use `pi = 22/7`)
The area of circle, inscribed in equilateral triangle is 154 cms2. Find the perimeter of
triangle.
The circumferences of two circles are in the ratio 2: 3. What is the ratio between their areas?
The shaded portion of the figure, given alongside, shows two concentric circles. If the circumference of the two circles is 396 cm and 374 cm, find the area of the shaded portion.
Each wheel of a car is of diameter 80 cm. How many completer revolutions does each wheel make in 10 minutes when the car is traveling at a speed of 66 km per hour?
Find the dimensions of a rectangular park whose perimeter is 60 m and area 200 m2.
The perimeter of circular and square fields is equal. If the area of the square field is 484 m2 then the diameter of the circular field is ____________.
A race track is in the form of a circular ring whose outer and inner circumferences are 396 m and 352 m respectively. The width of the track is ____________.
A photograph of Billiard/Snooker table has dimensions as `1/10`th of its actual size as shown in the following figure:
The portion excluding six holes each of diameter 0.5 cm needs to be polished at rate of ₹ 200 per m2. Find the cost of polishing.
