Advertisements
Advertisements
Question
The base and hypotenuse of a right triangle are respectively 5 cm and 13 cm long. Its area is ______.
Options
25 cm2
28 cm2
30 cm2
40 cm2
Advertisements
Solution
The base and hypotenuse of a right triangle are respectively 5 cm and 13 cm long. Its area is 30 cm2.
In right angled triangle ABC having base 5 cm and hypotenuse 13 cm we are asked to find its area
Using Pythagorean Theorem
`AB^2 = AC^2 + BC^2`
Where, AB = hypotenuse = 13 cm, AC = Base = 5 cm, BC = Height
`(13)^2 = (5)^2 + BC^2`
`169 = 25 + BC^2`
`BC = sqrt( 169-25)`
BC = 12 cm
Area of a triangle, say A having base 5 cm and altitude 12 cm is given by
`A = 1/2 (" Base" xx " Height ")`
Where, Base = 5 cm; Height = 12 cm
`A = 1/2 (5 xx 12)`
A = (5 × 6)
A = 30 cm2
APPEARS IN
RELATED QUESTIONS
A park, in the shape of a quadrilateral ABCD, has ∠C = 90°, AB = 9 m, BC = 12 m, CD = 5 m and AD = 8 m. How much area does it occupy?
Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.
Two parallel side of a trapezium are 60 cm and 77 cm and other sides are 25 cm and 26 cm. Find the area of the trapezium.
Find the area of an equilateral triangle having each side x cm.
Mark the correct alternative in each of the following:
The sides of a triangle are 16 cm, 30 cm, 34 cm. Its area is
The base of an isosceles right triangle is 30 cm. Its area is
The sides of a triangle are 7 cm, 9 cm and 14 cm. Its area is
A square and an equilateral triangle have equal perimeters. If the diagonal of the square is \[12\sqrt{2}\] cm, then area of the triangle is
The sides of a triangle are 35 cm, 54 cm and 61 cm, respectively. The length of its longest altitude ______.
In a triangle, the sides are given as 11 cm, 12 cm and 13 cm. The length of the altitude is 10.25 cm corresponding to the side having length 12 cm.
