Advertisements
Advertisements
Question
The area of a rhombus is 84 m2. If its perimeter is 40 m, then find its altitude.
Advertisements
Solution
Area of the rhombus = 84 m2
Perimeter = 40 m
Now, we know: Perimeter of the rhombus = 4 x Side
\[ \therefore 40 = 4 \times\text{ Side }\]
\[\text{ Side }=\frac{40}{4}=10 m\]
Again, we know: Area of the rhombus = Side x Altitude
\[ \Rightarrow 84 = 10 \times \]Altitude
Altitude \[=\frac{84}{10}= 8.4 m\]
Hence, the altitude of the rhombus is 8.4 m.
APPEARS IN
RELATED QUESTIONS
The area of a rhombus is 240 cm2 and one of the diagonal is 16 cm. Find another diagonal.
A rectangular grassy plot is 112 m long and 78 m broad. It has a gravel path 2.5 m wide all around it on the side. Find the area of the path and the cost of constructing it at Rs 4.50 per square metre.
Find the area of the field in the form of a rhombus, if the length of each side be 14 cm and the altitude be 16 cm.
The cost of fencing a square field at 60 paise per metre is Rs 1200. Find the cost of reaping the field at the rate of 50 paise per 100 sq. metres.
A field in the form of a rhombus has each side of length 64 m and altitude 16 m. What is the side of a square field which has the same area as that of a rhombus?
The area of a rhombus is equal to the area of a triangle whose base and the corresponding altitude are 24.8 cm and 16.5 cm respectively. If one of the diagonals of the rhombus is 22 cm, find the length of the other diagonal.
Find the area of the following polygon, if AL = 10 cm, AM = 20 cm, AN = 50 cm, AO = 60 cm and AD = 90 cm.
Find the area of the following regular hexagon.
Polygon ABCDE is divided in different parts as shown in figure. If AD = 8 cm, AH = 6 cm, AG = 4 cm, AF = 3 cm and BF = 2 cm, CH = 3cm, EG = 2.5 cm. Then find the area of the polygon.

