Advertisements
Advertisements
Question
In exchange of a square plot one of whose sides is 84 m, a man wants to buy a rectangular plot 144 m long and of the same area as of the square plot. Find the width of the rectangular plot.
Advertisements
Solution
Given:
Side of the square plot = 84 m
Now, the man wants to exchange it with a rectangular plot of the same area with length 144.
\[ {\text{ Area of the square plot }= 84\times84 = 7056 m}^2 \]
∴ Area of the rectangular plot = Length x Width
7056 = 144 x Width
\[ \Rightarrow\text{ Width }=\frac{7056}{144}=49 m\]
Hence, the width of the rectangular plot is 49 m.
RELATED QUESTIONS
Find the area of a rhombus whose side is 5 cm and whose altitude is 4.8 cm. If one of its diagonals is 8 cm long, find the length of the other diagonal.
A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080 m2?
A rectangular grassy plot is 112 m long and 78 m broad. It has a gravel path 2.5 m wide all around it on the side. Find the area of the path and the cost of constructing it at Rs 4.50 per square metre.
The length of a side of a square field is 4 m. what will be the altitude of the rhombus, if the area of the rhombus is equal to the square field and one of its diagonal is 2 m?
The area of a rhombus is 84 m2. If its perimeter is 40 m, then find its altitude.
A garden is in the form of a rhombus whose side is 30 metres and the corresponding altitude is 16 m. Find the cost of levelling the garden at the rate of Rs 2 per m2.
The area of a rhombus is equal to the area of a triangle whose base and the corresponding altitude are 24.8 cm and 16.5 cm respectively. If one of the diagonals of the rhombus is 22 cm, find the length of the other diagonal.
Find the area of the following polygon, if AL = 10 cm, AM = 20 cm, AN = 50 cm, AO = 60 cm and AD = 90 cm.
A regular hexagon is inscribed in a circle of radius r. The perimeter of the regular hexagon is ______.
