Question

A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080 m²?

Answer 1

Given:
Base of a flooring tile that is in the shape of a parallelogram = b = 24 cm
Corresponding height = h = 10 cm
Now, in a parallelogram: 
Area(A) = Base (b) x Height (h)
\[ \therefore\text{ Area of a tile }= 24 cm \times 10 cm = 240 {cm}^2 \]
Now, observe that the area of the floor is 1080 \[m^2 . \]
\[1080 m^2 = 1080 \times 1m \times 1m\]
\[ = 1080 \times 100 cm \times 100 cm (\text{ Because }1 m = 100 cm)\]
\[ = 1080 \times 100 \times 100 \times cm \times cm\]
\[ = 10800000 {\text{ cm }}^2 \]
∴ Number of required tiles =\[ \frac{10800000}{240} = 45000\]

Hence, we need 45000 tiles to cover the floor.