Advertisements
Advertisements
प्रश्न
The area of a rhombus is 84 m2. If its perimeter is 40 m, then find its altitude.
Advertisements
उत्तर
Area of the rhombus = 84 m2
Perimeter = 40 m
Now, we know: Perimeter of the rhombus = 4 x Side
\[ \therefore 40 = 4 \times\text{ Side }\]
\[\text{ Side }=\frac{40}{4}=10 m\]
Again, we know: Area of the rhombus = Side x Altitude
\[ \Rightarrow 84 = 10 \times \]Altitude
Altitude \[=\frac{84}{10}= 8.4 m\]
Hence, the altitude of the rhombus is 8.4 m.
संबंधित प्रश्न
Mohan wants to buy a trapezium shaped field. Its side along the river is parallel to and twice the side along the road. It the area of this field is 10500 m2 and the perpendicular distance between the two parallel sides is 100 m, find the length of the side along the river.
A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080 m2?
A rectangular grassy plot is 112 m long and 78 m broad. It has a gravel path 2.5 m wide all around it on the side. Find the area of the path and the cost of constructing it at Rs 4.50 per square metre.
The length of a side of a square field is 4 m. what will be the altitude of the rhombus, if the area of the rhombus is equal to the square field and one of its diagonal is 2 m?
Find the area of the field in the form of a rhombus, if the length of each side be 14 cm and the altitude be 16 cm.
The cost of fencing a square field at 60 paise per metre is Rs 1200. Find the cost of reaping the field at the rate of 50 paise per 100 sq. metres.
A garden is in the form of a rhombus whose side is 30 metres and the corresponding altitude is 16 m. Find the cost of levelling the garden at the rate of Rs 2 per m2.
Find the area of the following polygon, if AL = 10 cm, AM = 20 cm, AN = 50 cm, AO = 60 cm and AD = 90 cm.
Find the area of the following regular hexagon.
A regular hexagon is inscribed in a circle of radius r. The perimeter of the regular hexagon is ______.
