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Question
The angle of depression of a car parked on the road from the top of a 150-m-high tower is 30°. The distance of the car from the tower is ______.
Options
`50sqrt(3)` m
`150sqrt(3)` m
`150sqrt(2)` m
75 m
MCQ
Fill in the Blanks
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Solution
The angle of depression of a car parked on the road from the top of a 150-m-high tower is 30°. The distance of the car from the tower is `underlinebb(150sqrt(3) m)`.
Explanation:
Let AB be the tower and C be the position of the car on the ground such that ∠ACB = 30°.
Let AC = x metres.
Then, `(AC)/(AB) = cot 30^circ`
⇒ `x/150 = sqrt(3)`
⇒ `x = 150sqrt(3)`
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