Advertisements
Advertisements
प्रश्न
The angle of depression of a car parked on the road from the top of a 150-m-high tower is 30°. The distance of the car from the tower is ______.
विकल्प
`50sqrt(3)` m
`150sqrt(3)` m
`150sqrt(2)` m
75 m
MCQ
रिक्त स्थान भरें
Advertisements
उत्तर
The angle of depression of a car parked on the road from the top of a 150-m-high tower is 30°. The distance of the car from the tower is `underlinebb(150sqrt(3) m)`.
Explanation:

Let AB be the tower and C be the position of the car on the ground such that ∠ACB = 30°.
Let AC = x metres.
Then, `(AC)/(AB) = cot 30^circ`
⇒ `x/150 = sqrt(3)`
⇒ `x = 150sqrt(3)`
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
