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The ages of 80 students (above 8 years) of a school are measured and tabulated as below: Age (in years) 8 – 10 below 12 below 14 below 16 below 18 Number of students 7 15 29 68 80 - Mathematics

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Question

The ages of 80 students (above 8 years) of a school are measured and tabulated as below:

Age (in years) 8 – 10 below 12 below 14 below 16 below 18
Number of students 7 15 29 68 80

Construct a frequency distribution table for the above data. Also, answer the following questions:

  1. How many students have at least 16 years age but less than 18 years? 
  2. How many students have at most 14 years age?
Sum
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Solution

Given: Ages of 80 students (above 8 years) are tabulated as: 8 – 10 : 7; below 12 : 15; below 14 : 29; below 16 : 68; below 18 : 80.

Step-wise calculation:

1. Take class intervals as:

8 – 10

10 – 12

12 – 14

14 – 16

16 – 18

2. Frequencies from cumulative (subtract previous cumulative):

8 – 10:

f1 = 7   ...(Given)

10 – 12:

f2 = (Below 12) – f1 

= 15 – 7

= 8

12 – 14:

f= (Below 14) – (Below 12)

= 29 – 15

= 14

14 – 16:

f= (Below 16) – (Below 14)

= 68 – 29

= 39

16 – 18:

f5 = (Below 18) – (Below 16)

= 80 – 68

= 12

Frequency distribution table:

Age (in years) Number of students
8 – 10 7
10 – 12 8
12 – 14 14
14 – 16 39
16 – 18 12
Total 80

i. Students with at least 16 but less than 18 years

= Frequency of 16 – 18 

= 12

ii. Students with at most 14 years age

= Cumulative up to 14

= 29

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Notes

The answer in the textbook is incorrect.

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Chapter 15: Statistics - Exercise 15A [Page 289]

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Nootan Mathematics [English] Class 9 ICSE
Chapter 15 Statistics
Exercise 15A | Q 16. | Page 289
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