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The abscissa of the point on the curve 3y = 6x – 5x3, the normal at which passes through origin is ______.

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Question

The abscissa of the point on the curve 3y = 6x – 5x3, the normal at which passes through origin is ______.

Options

  • 1

  • `1/3`

  • 2

  • `1/2`

MCQ
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Solution

The abscissa of the point on the curve 3y = 6x – 5x3, the normal at which passes through origin is 1.

Explanation:

Let (x1, y1) be the point on the given curve 3y = 6x – 5x3 at which the normal passes through the origin.

Then we have `("dy"/"dx")_(x_1, y_1)`

= `2 - 5x_1^2`.

Again the equation of the normal at (x1, y1) passing through the origin gives `2 - 5x_1^2`

= `(-x_1)/y_1`

= `(-3)/(6 - 5x_1^2)`.

Since x1 = 1 satisfies the equation.

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Chapter 6: Application Of Derivatives - Solved Examples [Page 132]

APPEARS IN

NCERT Exemplar Mathematics Exemplar [English] Class 12
Chapter 6 Application Of Derivatives
Solved Examples | Q 19 | Page 132
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