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Who that the Tangents to the Curve Y = 7x3 + 11 at the Points X = 2 and X = −2 Are Parallel ? - Mathematics

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Question

Who that the tangents to the curve y = 7x3 + 11 at the points x = 2 and x = −2 are parallel ?

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Solution

\[\text { Given: }y = 7 x^3 + 11\]

\[ \therefore \frac{dy}{dx} = 21 x^2 \]

\[\text { Now,} \]

\[\text { Slope of the tangent at } (x = 2) = \left( \frac{dy}{dx} \right)_{x = 2} = 21 \left( 2 \right)^2 = 84\]

\[\text { Slope of the tangent at } (x = - 2) = \left( \frac{dy}{dx} \right)_{x = - 2} = 21 \left( - 2 \right)^2 = 84\]

Both slopes are the same. Hence, the tangents at points x = 2 and x = −2 are parallel.

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Chapter 16: Tangents and Normals - Exercise 16.1 [Page 11]

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RD Sharma Mathematics [English] Class 12
Chapter 16 Tangents and Normals
Exercise 16.1 | Q 20 | Page 11

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