English

The 6th term from the end of the G.P. 8, 4, 2, ......., $$\frac{1}{1024}$$ is ______.

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Question

The 6th term from the end of the G.P. 8, 4, 2, ......., $$\frac{1}{1024}$$ is ______.

Options

  • $$\frac{1}{32}$$

  • $$\frac{1}{16}$$

  • $$\frac{1}{64}$$

  • $$\frac{1}{128}$$

MCQ
Fill in the Blanks
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Solution

The 6th term from the end of the G.P. 8, 4, 2, ......., $$\frac{1}{1024}$$ is `underlinebb(1/32)`.

Explanation:

The common ratio is $$\frac12$$. The sixth term from the end is $$\frac{1/1024}{(1/2)^5} = \frac{32}{1024} = \frac1{32}$$.

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Chapter 11: Geometric Progression - COMPETENCY-FOCUSED QUESTIONS [Page 182]

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R.S. Aggarwal Mathematics [English] Class 10 ICSE
Chapter 11 Geometric Progression
COMPETENCY-FOCUSED QUESTIONS | Q 18. | Page 182
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